How can i get release label by release id.
It is pretty obvious.
Although I don’t really understand what you want.
See right-hand sidebar where you get the two release labels Columbia and ISO Records.
Or by XML web service (inc=labels):
https://musicbrainz.org/ws/2/release/24d4159a-99d9-425d-a7b8-1b9ec0261a33?inc=labels
Or by JSON web service (inc=labels):
https://musicbrainz.org/ws/2/release/24d4159a-99d9-425d-a7b8-1b9ec0261a33?inc=labels&fmt=json
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Do you mean from the web service or via SQL queries?
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Label {#268 ▼
-relations: LabelRelationList {#250 
}
-aliases: AliasList {#267 }
-area: Area {#275 }
-country: Country {#296 }
-disambiguation: Disambiguation {#297 }
-ipis: IPIList {#298 }
-isnis: ISNIList {#299 }
-labelCode: LabelCode {#300 }
-labelType: LabelType {#301 }
-lifeSpan: LifeSpan {#302 }
-MBID: MBID {#306 ▼
-mbid: “”
}
-name: Name {#307 ▼
-name: “”
}
i am using guzzle to call api but not get lable anyhow in any release lookup request.
Which endpoint do you/guzzle query then?
For a browse request, you should use inc=labels parameter, for example:
https://musicbrainz.org/ws/2/release/bb47369f-f4f9-4330-b377-ac9a9c4abb3b?inc=labels
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